The Tournament Director Forums
Main => Help Me => Topic started by: Johnfolds on October 05, 2012, 11:45:27 AM

Hi everyone,
I'm writing here from France: I am the president of a poker club (association) and I would loke to know if someone could help me to make my formula for our tournaments.
here is the situation:
 we usually make 1/3 of ITM: so if n represent the amount of players ITM is when r<=n/3.
 we use the "winamax formula which includes the "winamax point factor". That factor is the one that bothers me.
 the original formula is:
{[sqrt(n/(pow(r,exp(10/n))]/Y}*b*n
where
n= number of players
r= rank
Y= sum of winamax point. each ITM player as a Winamax point x(r)=sqrt(n/(pow(r,exp(10/n))
I made my formula for 63 player (Y=53.45) and it's ok. But I don't know how to make a general formula for n players. In fact I don't know how to introduce the "x" or the "Y" variable.
If you can help I would be grateful.
Thanks a lot.
Johnfolds

I'll try to help, but I'm a bit confused.
{[sqrt(n/(pow(r,exp(10/n))]/Y}*b*n
Should translate easily enough. But, what is b?
Y= sum of winamax point. each ITM player as a Winamax point x(r)=sqrt(n/(pow(r,exp(10/n))
You say Y is the sum of the winamax point(s) and then define what the winamax point formula is. So, is Y the same as sqrt(n/(pow(r,exp(10/n))? Or is it the sum of ... something else? Or, is sqrt(n/(pow(r,exp(10/n)) just part of the main formula above?

yop yop,
actually I forgot some details.
b = buyin per players (260 points per players in this example)
for the winamax calcul part Y = sum of all x(p).
for example for a 63 players tournament the winamax points for each 21 ITM players ares:
1st 7.94
2nd 5.29
3rd 4.17
4th 3.52
5th 3.09
6th 2.78
7th 2.54
8th 2.35
9th 2.19
10th 2.06
11th 1.95
12th 1.85
13th 1.77
14th 1.69
15th 1.62
16th 1.56
17th 1.51
18th 1.46
19th 1.41
20th 1.37
21th 1.33
The total of all these points is Y (53.45 here)
For the formula it could be simple in writing with:
(x(p)/Y)*b*n
where x(p)= (sqrt(n/(pow(r,exp(10/n)))))
Y= sum of all x(p)
I hope my explanations are more simple.
Johnfods

I tried to write this formula for test but it does not work.. :(
if (r <= n/3, (sqrt(n/(pow(r,exp(10/n)))))/53.45*260*63)
260 = buyin points for each players
63 = total players
Please help mister Cooper. ;)
Johnfolds

I'm afraid I'm just as confused as before. I think.
Y= sum of all x(p)
So the issue, IF I understand this, is that Y is supposed to be the sum of all x(p), where x(p) is sqrt(n/(pow(r,exp(10/n)))) as computed for each player. And there's the issue. When the software computes the formula value for each player, it cannot compute values as applied to other players. In the case of sqrt(n/(pow(r,exp(10/n)))) the only variable that would change is r, or the player's rank, so this could be done by "looping" from 1 through n (where n is the number of players), but there's no "looping" logic in formulas, either.
The trick would be to find a formula equivalent of the summation part. For example, the sum of the number from 1 to n is (n * (n+1) / 2). But wouldn't even know where to begin to transform sqrt(n/(pow(r,exp(10/n)))) into an equivalent formula, if it's even possible. Here's what Wolfram breaks it into:
http://www.wolframalpha.com/widget/widgetPopup.jsp?p=v&id=d983db47634e1936eb568b79884012ac&title=Summation%20Calculator&theme=blue&i0=sqrt(n/(r%5Eexp(10/n)))&i1=1&i2=63&podSelect=&includepodid=Result&showAssumptions=1&showWarnings=1