Author Topic: Chops  (Read 702 times)

capers

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Chops
« on: September 24, 2018, 11:45:49 AM »
When chopping 2 players the player with the smaller amount of chips gets less than 2nd place prize money. What am I doing wrong? If this is correct, what is the logic? Thanks!
Bill

Corey Cooper

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Re: Chops
« Reply #1 on: September 24, 2018, 03:29:38 PM »
When chopping any number of players, the prize money that goes with the ranks those players get is combined and divided evenly.  If you choose to divvy up based on chip stacks, the chip stacks you enter create percentages, which is how the money will be divided.  The chop process doesn't take into account if a specific player will have a lower amount than any particular prize (it probably should, but it does not currently).

To take your example, let's say the prizes are $1000 and $600 for 1st and 2nd place, and the last 2 players decide to chop.  If one player has 5000 in chips and the other player has 1500, that makes it:

6500 total chips
First player has 5000/6500 = 76.9% of the chips
Second player has 1500/6500 = 23.1% of the chips

So, first place would get $1600 X 76.9% = $1230.40
and second place would get $1600 X 23.1% = $369.60

Obviously second place would not go for this, because the chop is worth less than playing it out.

Using the ICM would yield something much more reasonable:

First place: $907.69
Second place: $692.31

ICM is definitely on my radar to add (along with lots of other things) once I get past the current issues and get the next version out.

capers

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Re: Chops
« Reply #2 on: September 25, 2018, 02:20:32 PM »
Thanks Corey!
           Bill